CLASS:- 9 EXERCISE:- 4.1 LINEAR EQUATIONS IN TWO VARIABLES ALL SOLUTION

CLASS :- 9, EX :- 4.1



1.    The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.

(Take the cost of a notebook to be ₹ x and that of a pen to be ₹ y).

solution :

Let the cost of a notebook to be = ₹ x

Let the cost of a pen to be = ₹ y

According to the question,

Cost of a notebook = 2 × Cost of a pen

` \x = 2 × y\ `

` \x=2y\ `

` \x−2y = 0\ `

The cost of a notebook is twice the cost of a pen.

2.    Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:

(i)  ` \2x+3y=9.3 \overline5 \ `

(ii)  ` \x-\frac{y} {5} -10=0\ `

(iii)  ` \-2x+3y=6\ `

(iv)  `\x=3y\ `

(v)  ` \2x=-5y\ `

(vi)  ` \3x+2=0\ `

(vii)  `\y-2=0\ `

(viii)  ` \5=2x\ `

solution :

(i)  ` \2x+3y=9.3 \overline5 \ `

  ` \2x+3y=9.3 \overline5 \ ` can be written as ` \2x+3y-9.3\overline5=0 \ `

Now, comparing ` \2x+3y-9.3\overline5=0 \ ` with ` \ax+by+c=0 \ `

Here,

` \a=2\ `

` \b=3\ `

` \c= -9.3 \overline5 \ `

(ii)  ` \x-\frac{y} {5} -10=0\ `

  ` \x-\frac{y} {5} -10=0\ ` can be written as ` \1x-\frac{1} {5}y -10=0\ `

Now, comparing ` \1x-\frac{1} {5}y -10=0\ ` with ` \ax+by+c=0 \ `

Here,

` \a=1\ `

` \b=\frac{1} {5}\ `

` \c= -10 \ `

(iii)  ` \-2x+3y=6\ `

  ` \-2x+3y=6\ ` can be written as ` \-2x+3y-6=0\ `

Now, comparing ` \-2x+3y-6=0\ ` with ` \ax+by+c=0 \ `

Here,

` \a=-2\ `

` \b=3\ `

` \c= -6 \ `

(iv)  `\x=3y\ `

  `\x=3y\ ` can be written as ` \1x-3y+0=0\ `

Now, comparing ` \1x-3y+0=0\ ` with ` \ax+by+c=0 \ `

Here,

` \a=1\ `

` \b=-3\ `

` \c= 0 \ `

(v)  ` \2x=-5y\ `

  ` \2x=-5y\ ` can be written as ` \2x+5y+0=0\ `

Now, comparing ` \2x+5y+0=0\ ` with ` \ax+by+c=0 \ `

Here,

` \a=2\ `

` \b=5\ `

` \c=0 \ `

(vi)  ` \3x+2=0\ `

  ` \3x+2=0\ ` can be written as ` \3x+0y+2=0\ `

Now, comparing ` \3x+0y+2=0\ ` with ` \ax+by+c=0 \ `

Here,

` \a=3\ `

` \b=0\ `

` \c= 2 \ `

(vii)  `\y-2=0\ `

  `\y-2=0\ ` can be written as ` \0x+1y-2=0\ `

Now, comparing ` \0x+1y-2=0\ ` with ` \ax+by+c=0 \ `

Here,

` \a=0\ `

` \b=1\ `

` \c= -2 \ `

(viii)  ` \5=2x\ `

  ` \5=2x\ ` can be written as ` \-2x+0y+5=0\ `

Now, comparing ` \-2x+0y+5=0\ ` with ` \ax+by+c=0 \ `

Here,

` \a=-2\ `

` \b=0\ `

` \c= 5 \ `



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